Question

dos termos da PG(2,4,...,1024

Answer 1

Ola 

PG

u1 = 2
u2 = 4

q = u2/u1 = 4/2 = 2

termo geral

un = u1*q^(n - 1)

2*2^(n - 1) = 1024

2^(n - 1) = 512 = 2^9 

n = 10 termos

Soma

Sn = u1*(q^n - 1)/(q - 1)
Sn = 2*(2^10 - 1)/(2 - 1)

Sn = 2*(1024 - 1) = 2*1023 = 2046 

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