Question

fórmula de Bhaskara encontre o valor de X' e X" , X²+12x-28=0

Answer 1

x² +12x -28= 0

Fórmula de Bháskara:
delta= b² -4.a.c
delta= 12² -4.1.(-28)
delta= 144 +112
delta= 256

x= -b +/-raiz quadrada de delta /2.a
x= -12 +/-raiz quadrada de 256 /2.1
x= -12 +/-16 /2

x'= -12 +16 /2
x'= 4/2
x'=2

x''= -12 -16 /2
x''= -28/2
x''= -14