Question

interpole 12 meios aritméticos entre 3/4 e 11/6?

Answer 1

A 14 = 11/6
A 14 = A1 + (N - 1).R
A 14 = 3/4 + (14 - 1 ).R
A 14 = 3/4  + 13 R
11/6 = 3/4 + 13 R
11/6 - 3/4 = 13 R
M.M.C = 12
22/12 - 9/12 = 13 R
13/12 = 13 R
13 R = 13/12
R = 13/12 X 1/13 SIMPLIFICA = 1/12
P.A.(3/4,10/12,11/12,12/12,13/12,14/12,15/12,16/12,17/12,18/12,19/12,20/12,21/12,22/12,( SIMPLIFICA =11/6)
A 2 = 3/4 + 1/12 = 10/12
A 3 = 10/12 + 1/12 = 11/12
A 4 = 11/12 + 1/12 = 12/12
A 5 = 13/12 + 1/12 = 13/12
A 6 = 14/12 + 1/12 = 14/12
A 7 = 15/12 + 1/12 = 15/12
A 8 = 16/12 + 1/12 = 16/12
A 9 = 17/12 + 1/12 = 17/12
A 10 = 18/12 + 1/12 = 18/12
A 11 = 19/12 + 1/12 = 19/12
A 12 = 20/12 + 1/12 = 20/12
A 13 = 21/12 + 1/12 = 21/12
A 14 = 22/12 + 1/12 = 22/12(simplifica) = 11/6