Question

achar raizes das equacoes x2+4x-12=0??

Answer 1

(4)^2-4.1.-12
16+48
∆=64

(-4+-√∆)/2.1

x'= (-4+8)/2=2
x"= (-4-8)/2=-6

Answer 2

(4)^2-4.1.-12
16+48
∆=64
(-4+-√∆)/2.1
x'= (-4+8)/2=2
x"= (-4-8)/2=-6