Question

x2+4x-5=0 soluções das equações

Answer 1

x²+4x-5
Δ= b² - 4 ac
Δ= 4² - 4 . 1 . (-5)
Δ= 16 + 20
Δ= 36

x= -b ± √Δ / 2a
x= -4  ± √36 / 2.1
x= -4  ± 6 /2
x'= -4 + 6 / 2
x'= 2 /2
x'=1

x''= -4 -6/2
x''= -10 /2
x''= -5

Answer 2

$x^{2} +4 x - 5 = 0$

$\frac{-b \pm \sqrt{-b^2 -4*a*c}}{2*a}$

Vamos encontrar o valor de Delta

Δ=b2−4ac
Δ=(4)2−4*(1)*(−5)
Δ=16+20
Δ=36

$x = \frac{-b \pm \sqrt{\triangle}}{2*a} \\ \\ x= \frac{-4 \pm \sqrt{36}}{2*1} \\ \\ x= \frac{-4 \pm 6}{2} \\ \\ \\ x'= \frac{-4 + 6}{2} \\ \\ x'= \frac{2}{2} \\ \\ x' = 1 \\ \\ \\ x''= \frac{-4 - 6}{2} \\ \\ x''= \frac{-10}{2} \\ \\ x'' = - 5 \\ \\ \\ S = \left \{ 1, - 5} \right. \}$