Question

o valor de (1+i)^6 é

Answer 1

$i^2 = -1\\ i^3=i^2 \cdot i=-1\cdot i=- i\thereforei^3=-i\\ \\ \\ \\(i+1)^6=[(i+1)^2]^3=[i^2+2i+1]^3=[-1+2i+1]^3=[2i]^3=2^3\cdot i^3\\ \\=8\cdot (-i)=-8i$