Question

balanceamento? alguém?

Answer 1

multiplique as bases por 2

Answer 2

Resposta:

CrCl₃ +NaClO₃+NaOH  --> Na₂CrO₄+NaCl+H₂O

a*CrCl₃ +b*NaClO₃+c*NaOH  --> d*Na₂CrO₄+ e* NaCl + f * H₂O

a=d

3a+b=e  ==>  3a+2a/3=e  ==>e=11a/3

b+c=d+e    ==>b+c=d+3a+b ==>b+c=4a+b ==>c=4a

3b+c=4d+f  ==>3b+2f=4d+f ==>f= 4d-3b

c=2f  ==>f=2a

2a=4d-3b

2a=4a-3b

3b=2a  ==>b=2a/3

a*CrCl₃ +2a/3*NaClO₃+4a*NaOH  --> a*Na₂CrO₄+ 11a/3* NaCl + 2a * H₂O

fazendo a=1

CrCl₃ +2/3*NaClO₃+4*NaOH  --> Na₂CrO₄+ 11/3* NaCl + 2 * H₂O

3CrCl₃ +2NaClO₃+12NaOH  --> 3Na₂CrO₄+ 11* NaCl + 6 H₂O