Question

considerando log10 2 = 0,301 e log10 3= 0,477,então log10 450 sera igual a: a)45 b)0,667 c)2,500 d)2,653 e)2,454

Answer 1

$\mathsf{\ell og(2)\approx 0,301}\\\mathsf{\ell og(3)\approx 0,477}\\\\\mathsf{\ell og (450)=x}\\\\\mathsf{\ell og(3\cdot3\cdot\frac{100}{2})=x}\\\mathsf{\ell og(3)+\ell og(3)+\ell og(100)-\ell og(2)=x}\\\mathsf{2\cdot(0,477)+2-0,301=x}\\\mathsf{0,954+1,699=x}\\\\\boxed{\mathsf{x=2,653}}$

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