Question

Determine a lei que define a função Y0F e F0Y em cada caso:
a)F(x)=2x, y(x)=4x+1
b)F(x)=6-x, h(x)=6x+3

Answer 1

a)F(x)=2x, y(x)=4x+1


Y0F = Y(F(x)) = 4(2x) + 1 ==> 8x + 1

F0Y = F(Y)) = 2(4x+1) ==> 8x + 2
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b)F(x)=6-x, h(x)=6x+3


H0F = H(F(x)) = 6(6-x) + 3 ==> 36 - 6x + 3 ==> 39 - 6x

F0H = F(H)) = 6 - (6x+3) ==> 6 - 6x - 3 ==> - 6x + 3