Question

Se log x = log b^3 + 4 log c - 1/4 log a, qual o valor de x em função de a, b e c?

Answer 1

$logx=log b^{3} +4logc- \frac{1}{4} loga$

$logx=log b^{3} +log c^{4} -log a^{ \frac{1}{4} }$

$logx=log( \frac{b^{3} * c^{4}}{ \sqrt[4]{a} } )$

$x= \frac{ b^{3}* c^{4} }{ \sqrt[4]{a} }$