Question

construa a matriz quadrada c=(cij)4x4 , tal que cij = 3i³+ j



me ajudem ai pfv

Answer 1

4 LINHAS e 4 COLUNAS

cij = 3i³ + j
c11 = 3.1³ + 1 = 3.1 + 1 = 3 + 1 = 4
c12 = 3.1³ + 2 = 3.1 + 2 = 3 + 2 = 5
c13 = 3.1³ + 3 = 3.1 + 3 = 3 + 3 = 6
c14 = 3.1³ + 4 = 3.1 + 4 = 3 + 4 = 7
c21 = 3.2³ + 1 = 3.8 + 1 = 24 + 1 = 25
c22 = 3.2³ + 2 = 3.8 + 2 = 24+ 2 = 26
c23 = 3.2³ + 3 = 3.8 + 3 = 24 + 3 = 27
c24 = 3.2³ + 4 = 3.8 + 4 = 24 + 4 = 28
c31 = 3.3³ + 1 = 3.27 + 1 = 81 + 1 = 82
c32 = 3.3³ + 2 = 3.27 + 2 = 81 + 2 = 83
c33 = 3.3³ + 3 = 3.27 + 3 = 81 + 3 = 84
c34 = 3.3³ + 4 = 3.27 + 4 = 81 + 4 = 85
c41 = 3.4³ + 1 = 3.64 + 1 = 192 + 1 = 193
c42 = 3.4³ + 2 = 3.64 + 2 = 192 + 2 = 194
c43 = 3.4³ + 3 = 3.64 + 3 = 192 + 3 = 195
c44 = 3.4³ + 4 = 3.64 + 4 = 192 + 4 = 196

C = [  4      5       6       7]
      [ 25   26     27      28]
      [  82   83      84    85]
      [193  194   195   196]