Question

Dados:log2=0,301 e log3 =0,477 calcule log 16

Answer 1

A) log 8 = log 2^3 = 3 log 2 = 3 * 0,301 = 0,903 


B) log 12 = log 3 * 4 = log 3 + log 4 = log 3 + log 2^2 = log 3 + 2 log 2 = 0,477 + 2 * 0,301 = 1,079 


C) log 54 = log 2 * 27 = log 2 + log 3^3 = log 2 + 3 log 3 = 0,301 + 3 * 0,477 = 1,732Fonte(s):Eu mesmo