Question

F (x)=x2+5x-4 calcule f (2)+3 [f (3)]-f (1)

Answer 1

f(2) = 2^2 + 5 x 2 - 4 = 4 + 10 - 4 = 10
f(3) = 3^2 + 5 x 3 - 4 = 9 + 15 - 4 = 20
f(1) = 1^2 + 5 x 1 - 4 = 1 + 5 - 4 = 2

f(2) + 3 [f(3)] - f(1) = 10 + 3 (20) - 2 --> 10 + 60 - 2 = 70 - 2 = 68