Question

os zeros da funçao f (x)= -x2+6x-5

Answer 1

f (x)= -x²+6x-5

Δ=36-4.(-1).(-5)
Δ=16

x1= -6+4/2.(-1)
x1= 1

x2= -6-4/2.(-1)
x2= 5

;)

Answer 2

f(x) = - x² + 6x - 5
0 = - x² + 6x - 5
- x² + 6x - 5 = 0 (-1)
x² - 6x + 5 = 0
a = 1; b = - 6; c = 5
Δ = b² - 4ac
Δ = (-6)² - 4.1.5
Δ = 36 - 20
Δ = 16

x = - b +/- √Δ    = - (-6) +/- √16
       --------------    --------------------
              2a                    2.1

x = 6 + 4
      --------  = 10/2 = 5
          2

x = 6 - 4
      --------  = 2/2 = 1
          2

R.: x = 1 e x = 5