Question

y=x2-6x+8 determina o zero da funçao

Answer 1

x² - 6x + 8 = 0
Δ = 36 - 32
Δ = 4
$x = \frac{-(-6) \pm 2}{2} \\ \\ x' = \frac{6+2}{2} = 4 \\ \\ x'' = \frac{6-2}{2} =2$


y = 0 quando x = 4 ou x = 2