Question

Dada a função f(x)=2x²-6x-8 , calcule f(2) + 3 [f (3)]-f (1)

Answer 1

f(x)=2x²-6x-8
f(2)=8-12-8
f(2)=-12

f(3)=18-18-8
f(3)=-8

f(1)=2-6-8
f(1)=-12

f(2)+ 3(f(3)-f(1)
-12+3(-8)-(-12)
-12-24+12
-24