• Matéria: Matemática
  • Autor: Anna666
  • Perguntado 8 anos atrás

a) A=(3/4)^2.(-2)^3+(-1/2)^1 b) B=(1/2)^-2+(1/3)^-1 c) C=-2.(3/2)^3+1^15-(-2)^1 d) D=[(-5/3)^-1+(5/2)^-1]^-1 e) E=[3^-1-(-3)^-1]^-1 f) F=6.(2/3)^2+4.(-3/2)^-2 calcule o valor das expressões

Respostas

respondido por: juliemat
3
a) A=(3/4)^2.(-2)^3+(-1/2)^1 b)
9/16.-8-1/2=
- 72/16 -1/2=. mmc(16)
-72-8/16=
-80/16= -5

B=(1/2)^-2+(1/3)^-1
(2)^2+(3)^1=
4+3=7

c) C=-2.(3/2)^3+1^15-(-2)^1
2.27/8+1+2
48/8+3 mmc(8)
48+24/8=
72/8=9


d) D=[(-5/3)^-1+(5/2)^-1]^-1
[-3/5+2/5]^-1
[-1/5]^-1=
-5^1= -5




e) E=[3^-1-(-3)^-1]^-1
1/3-1/3-1= -1

f) F=6.(2/3)^2+4.(-3/2)^-2
6.(4/9+4.(-2/3)^2
6.4/9+4.4/9
24/9+16/9=
40/9
boa sorte

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