Question

Calcule os logaritmos:

a) ㏒₂ 1/32 b)㏒₂ √32

Answer 1

A -

$\log _{2}\frac{1}{32}=x\\ \\ 2^{x} =\frac{1}{32}\\ \\ 2^{x}=2^{-5}\\ \\ x = -5$



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B - 

$\log _{2}32 = x\\ \\2^{x}=32\\ \\ 2^{x} = 2^{5}\\ \\ x = 5$