Question

se x= log1/2 16 raiz quinta de 2 e y= (2)elevado a 2 log 3 7*log de 2 elevado a 3, o valor de 5x+y é ??

Answer 1

$x=\log_{\frac12}(16\sqrt[5]{2})\\\\(\frac12)^x=16\sqrt[5]{2}\\\\2^{-x}=2^4\cdot2^{\frac15}\\\\-x=\frac{21}{5}\\\\x=-\frac{21}{5}\\\\y=2^{2\log_37\cdot\log_23}\\\\y=(2^{\log_23})^{\log_349}\\\\y=(3)^{\log_349}\\\\y=49\\\\5(-\frac{21}5)+49=-21+49=28$

Answer 2

Boa tarde Leila

x = log1/2(16*⁵√2) = -log2(16) - log2(2)/5 
x = -log2(2^4) - 1/5 
x = -4 - 0.2 = -4.2

y = 2^(2log3(7)*log2(3) 
y = 2^(2log(7)/log(3)*log(3)/log(2)
y = 2^(2log(7)/log(2) 
y = 49 

5x + y = -5*4.2 + 49 = -21 + 49 = 28 (E)