Question

Calcule:
(4x - 3y + 2)² + (2x + 4y - 10)² = 0.

Answer 1

Boa tarde Vitor

4x - 3y + 2 = 0
2x + 4y - 10 = 0

sistema

4x - 3y = -2
4x + 8y = 20

8y + 3y = 20 + 2
11y = 22
y = 2

2x + 8 = 10
2x = 2
x = 1

S = (1,2) 

Answer 2

 

(4x - 3y + 2)² + (2x + 4y - 10)² = 0

(4x - 3y + 2)² = 4x(4x - 3y + 2) - 3y(4x - 3y + 2) + 2(4x - 3y + 2)

16x² - 12xy + 8x - 12xy + 9y² - 6y + 8x - 6y + 4

==> 6x² - 24xy + 16x + 6y² - 12y + 4  
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(2x + 4y - 10)² = 2x(2x + 4y - 10) + 4y(2x + 4y - 10) - 10(2x + 4y - 10)


4x² + 8xy - 20x + 8xy + 16y² - 40y - 20x - 40y + 100 

==> 4x² + 16xy - 40x + 16y² - 80y + 100