Question

calcule os f das funções quadrática f(x) = 2.(x+3)2 + 4 A) f(-1) B) f(-1) +2.f(0) =

Answer 1

$f(x) = 2 (x+3)^{2} + 4 \\ f(x) = 2 x^{2} +12x+22$

A)

$f(-1) = 2 (-1)^{2} +12(-1)+22 \\ f(-1) = 12$

B)
$f(0) = 2 (0)^{2} + 12(0) + 22 \\ f(0) = 22$
logo

12 + 2* 22 = 56