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![\bullet\,\,\sqrt[n]{a^{m}}=a^{(m/n)}\\\\\bullet\,\,\log_{a}a=1~~\mathsf{para~todo~a~\textgreater~0~e~a\neq1}\\\\\bullet\,\,\log_{b}a^{n}=n\cdot\log_{b}a](https://tex.z-dn.net/?f=%5Cbullet%5C%2C%5C%2C%5Csqrt%5Bn%5D%7Ba%5E%7Bm%7D%7D%3Da%5E%7B%28m%2Fn%29%7D%5C%5C%5C%5C%5Cbullet%5C%2C%5C%2C%5Clog_%7Ba%7Da%3D1%7E%7E%5Cmathsf%7Bpara%7Etodo%7Ea%7E%5Ctextgreater%7E0%7Ee%7Ea%5Cneq1%7D%5C%5C%5C%5C%5Cbullet%5C%2C%5C%2C%5Clog_%7Bb%7Da%5E%7Bn%7D%3Dn%5Ccdot%5Clog_%7Bb%7Da "\bullet\,\,\sqrt[n]{a^{m}}=a^{(m/n)}\\\\\bullet\,\,\log_{a}a=1~~\mathsf{para~todo~a~\textgreater~0~e~a\neq1}\\\\\bullet\,\,\log_{b}a^{n}=n\cdot\log_{b}a")
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![\log_{7}\sqrt{7}=\log_{7}\sqrt[2]{7^{1}}\\\\\log_{7}\sqrt{7}=\log_{7}7^{(1/2)}\\\\\\\log_{7}\sqrt{7}=\dfrac{1}{2}\cdot\log_{7}7\\\\\\\log_{7}\sqrt{7}=\dfrac{1}{2}\cdot1\\\\\\\boxed{\boxed{\log_{7}\sqrt{7}=\dfrac{1}{2}}}](https://tex.z-dn.net/?f=%5Clog_%7B7%7D%5Csqrt%7B7%7D%3D%5Clog_%7B7%7D%5Csqrt%5B2%5D%7B7%5E%7B1%7D%7D%5C%5C%5C%5C%5Clog_%7B7%7D%5Csqrt%7B7%7D%3D%5Clog_%7B7%7D7%5E%7B%281%2F2%29%7D%5C%5C%5C%5C%5C%5C%5Clog_%7B7%7D%5Csqrt%7B7%7D%3D%5Cdfrac%7B1%7D%7B2%7D%5Ccdot%5Clog_%7B7%7D7%5C%5C%5C%5C%5C%5C%5Clog_%7B7%7D%5Csqrt%7B7%7D%3D%5Cdfrac%7B1%7D%7B2%7D%5Ccdot1%5C%5C%5C%5C%5C%5C%5Cboxed%7B%5Cboxed%7B%5Clog_%7B7%7D%5Csqrt%7B7%7D%3D%5Cdfrac%7B1%7D%7B2%7D%7D%7D "\log_{7}\sqrt{7}=\log_{7}\sqrt[2]{7^{1}}\\\\\log_{7}\sqrt{7}=\log_{7}7^{(1/2)}\\\\\\\log_{7}\sqrt{7}=\dfrac{1}{2}\cdot\log_{7}7\\\\\\\log_{7}\sqrt{7}=\dfrac{1}{2}\cdot1\\\\\\\boxed{\boxed{\log_{7}\sqrt{7}=\dfrac{1}{2}}}")
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respondido por:
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㏒√7 B 7=log7^1/2 B 7=1/2log7B7=1/2
NB; B significa base
ESPERO QUE ENTENDA
NB; B significa base
ESPERO QUE ENTENDA
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