Respostas
respondido por:
0
= 25x⁴ - 16y²
= (5x²)² - (4y)²
= (5x² + 4y).(5x² - 4y)
= (5x²)² - (4y)²
= (5x² + 4y).(5x² - 4y)
respondido por:
3
Boa tarde Souza!
![25x^{4}-16y^{2} \\\\\\
(5 x^{2} \times5 x^{2}) -(4y \times4y) \\\\\\\
\boxed{(5 x^{2} -4y)\times(5 x^{2} +4y)}\\\\\\](https://tex.z-dn.net/?f=25x%5E%7B4%7D-16y%5E%7B2%7D+%5C%5C%5C%5C%5C%5C%0A%285+x%5E%7B2%7D+%5Ctimes5+x%5E%7B2%7D%29+-%284y+%5Ctimes4y%29+%5C%5C%5C%5C%5C%5C%5C%0A%5Cboxed%7B%285+x%5E%7B2%7D+-4y%29%5Ctimes%285+x%5E%7B2%7D+%2B4y%29%7D%5C%5C%5C%5C%5C%5C%0A%0A+ "25x^{4}-16y^{2} \\\\\\
(5 x^{2} \times5 x^{2}) -(4y \times4y) \\\\\\\
\boxed{(5 x^{2} -4y)\times(5 x^{2} +4y)}\\\\\\")
Bons estudos!
Bons estudos!
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