Respostas
respondido por:
1
Olá!
(2^n+3-2^n+1)/(2^n-1+2^n)
=> (2^n.2^3-2^n.2)/(2^n.2^-1+2^n)
=> 2^n(8-2)/2^n(1/2+1)
=> 6/3/2
=> 6×2/3
=> 12/3
=> 4
(2^n+3-2^n+1)/(2^n-1+2^n)
=> (2^n.2^3-2^n.2)/(2^n.2^-1+2^n)
=> 2^n(8-2)/2^n(1/2+1)
=> 6/3/2
=> 6×2/3
=> 12/3
=> 4
Perguntas similares
7 anos atrás
9 anos atrás
9 anos atrás
9 anos atrás
9 anos atrás