Question

4- obtenha o valor de x na figura sabendo que sen a = 0,6 e cos a = 0.8

Answer 1

$tg(a)= \frac{sen(a)}{cos(a)} = \frac{CatetoOposto}{Cateto Adjacente}$
$\frac{0.6}{0.8} = \frac{3x+2}{x+5}$
$\frac{3}{4} = \frac{3x+2}{x+5}$
$3*(x+5)=4*(3x+2)$
$3x+15=12x+8$
$12x-3x=15-8$
$9x=7$
$x= \frac{7}{9}$
$x=0.777...$