Question

D=[dij]4×2 onde dij= i2-3j+2

Answer 1

Boa noite Laraolx

D(1,1) = 1² - 3*1 + 2 = 0
D(1,2) = 1² - 3*2 + 2 = -3

D(2,1) = 2² - 3*1 + 2 = 3
D(2,2) = 2² - 3*2 + 2 = 0 

D(3,1) = 3² - 3*1 + 2 = 8 
D(3,2) = 3² - 3*2 + 2 = 5

D(4,1) = 4² - 3*1 + 2 = 15 
D(4,2) = 4² - 3*2 + 2 = 12