Question

O semiperímetro do triângulo ABC de vértices A (0,2), B (√3,5) e C (0,6) é
a) 6 + 2√3
b) 3 + √3
c) 6 + √3
d) 3 + 2√3

Answer 1

Boa tarde Lohcs

AB² = (Ax - Bx)² + (Ay - By)²
AB² = (0 - √3)² + (2 - 5)²
AB² = 3 + 9 = 12
AB = √12

AC² = (Ax - Cx)² + (Ay - Cy)²
AC² = (0 - 0)² + (2 - 6)²
AC² = 4² = 16
AC = 4

BC² = (Bx - Cx)² + (By - Cy)²
BC² = (√3 - 0)² + (5 - 6)²
BC² = 3 + 1 = 4
BC = 2

P = √12 + 4 + 2 = 2√3 + 6

P/2 = 3 + √3 (B)