Question

resolva as expressões numéricas
a)2+[3.4+2]+[2^5+5]
b)2+4[(5-3)+(7^-6^2)]
c)(√25-√16)^2-(√140-√169)^4
d)(11^2+5.4):3

Answer 1

A. $2 + (3*4 + 2) + (2^5+ 5) = \\ 2 + (12 + 2) + (32 + 5) = \\ 2 + 14 + 37 = 53$

B.$2 + 4[(5-3)+(7^2 -6^2)] = \\ 2 + 4[2 + (49 - 36)] = \\ 2 + 4[15] = \\ 2 + 60 = 62$

C.$( \sqrt{25} - \sqrt{16} )^2-( \sqrt{144} - \sqrt{169} )^4 = \\ ( 5 - 4)^2-( 12 - 13)^4 = \\ 2^2 - (-1)^4 = \\ 4 -1 = 3$

D.$\frac{(11^2+5*4)}{3} = \frac{(121 + 20)}{3} = \frac{141}{3} = 47$