Question

Perguntaaa urgenteee;
Responda as funções trigonométricas de acordo com o arco:
a) Tg 45 graus
b) cossec 135 graus
c) sen 315 graus
d) cos 30 graus
e) sen 240 graus
f) cotg 210 graus

Answer 1

a)
  tg45°=1

b)
    cossec135°=

$\frac{1}{sen45} = \frac{1}{ \frac{ \sqrt{2} }{2} } = \frac{2}{ \sqrt{2} } = \frac{2 \sqrt{2} }{ \sqrt{2}. \sqrt{2} } = \frac{2 \sqrt{2} }{ \sqrt{2^2} } = \frac{2 \sqrt{2} }{2} = \sqrt{2}$

c)
 sen315°⇒-sen45°= -√2/2

d)
  cos30°=√3/2

e)
  sen240°⇒-sen60°=-√3/2

f)
 cotg210°⇒cos210°÷sen210°=-cos30° ÷ -sen30°=

$(- \frac{ \sqrt{3} }{2} )\div(- \frac{1}{2} )=(- \frac{ \sqrt{3} }{2} )\times(-2)= \sqrt{3}$