Question

resolva a baskara x (ao quadrado) -9x +20=0

Answer 1

x² - 9x + 20 = 0
Δ = (-9)² - 4(1)(20)
Δ = 81 - 80
Δ = 1
$x = \frac{-(-9)\pm1}{2}$
x' = 5
x'' = 4

Answer 2

x² - 9x + 20 = 0

Δ = (-9)² - 4(1)(20)

Δ = 81 - 80

Δ = 1

x' = 5

x'' = 4