• Matéria: Matemática
  • Autor: claradelourdes
  • Perguntado 9 anos atrás

1°)Resolva os produtos notaveis
a) (x+9)^{2}
b) (y-12)^{2}
c) (k^{2}+5m) ^{2}
d)  (\frac{x}{3}-0,5m ^{9}) ^{2}
e)(y+3).(y-3)
f)(2k- a^{2} b^{3})(2k+a^{2} b^{3})

Respostas

respondido por: Anônimo
0
A) (x+9)²=
x²+2x*9+9²
x²+18x+81

B)(y-12)²=
y²-2y*12+12²
y²-24y+144

C)(k²+5m)²=
(k²)²+2k²*5m+(5m)²
 k^{4}+10k^{2}m+25m^{2}

D)( \frac{x}{3}-0.5m^{9})^{2}
 \frac{ x^{2} }{9} -2* \frac{x}{3}*0,5m^{9}+0,5^{2}*m^{18}
 \frac{ x^{2} }{9} -2* \frac{x}{3}* \frac{5}{10}m^{9}+( \frac{5}{10})^{2}*m^{18}
 \frac{x^{2} }{9}-2* \frac{x}{3}* \frac{1}{2}m^{9}+ (\frac{1}{2}^{2} ) *m^{18}
 \frac{x^{2} }{9} -  \frac{x}{3}*m^{9}  +  \frac{1}{4} m^{18}  \frac{ x^{2} }{9} -   \frac{ m^{9}x }{3} +  \frac{1}{4}m^{18}

E)(y+3)*(y-3)=
y²-3²
y²-9

F)(2k-a²b³)(2k+a²b³)
(2k)²-(a²b³)²
4k^{2}-a^{4}b^{6}
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