• Matéria: Matemática
  • Autor: novamenteagosto
  • Perguntado 9 anos atrás

resolva as seguintes equaçoes
a)(10x-10y)elevado a 3
b)(1,5y-1,52 )elevado a2

Respostas

respondido por: Irysbm14
0
RESPOSTAS FINAIS

a)(10x-10y)³= 1000x³-3000x²y+ 3000xy²-1000y³

b)(1,5y-1,52)²= 2,25y²-4,56y+2,3104

CÁLCULOS:

a)(10x-10y)³(propriedade distributiva)
(10x-10y).(10x-10y).(10x-10y)
100x²-100xy-100xy+100y².(10x-10y)
(100x²-200xy+100y²).(10x-10y)
1000x³-1000x²y-2000x²y+2000xy²+1000xy²-1000y³
1000x³-3000x²y+ 3000xy²-1000y³


-------------------

b)(1,5y-1,52)²
(1,5y-1,52).(1,5y-1,52)
2,25y²-2,28y-2,28y+2,3104
2,25y²-4,56y+2,3104

RESPOSTAS FINAIS

a)(10x-10y)³= 1000x³-3000x²y+ 3000xy²-1000y³

b)(1,5y-1,52)²= 2,25y²-4,56y+2,3104
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