• Matéria: Matemática
  • Autor: juUfam
  • Perguntado 9 anos atrás

Sejam P(1,-1,2) u (3,-3,1) v (1,1,1) Obtenha a tripla de coordenadas de (p-2u)+v

Respostas

respondido por: andresccp
2
P=(1,-1,2)\\U=(3,-3,1)\\V=(1,1,1)\\\\\ [P-2U]+V = [(1,-1,2)-2(3,-3,1)]+(1,1,1)\\\\\ [P-2U]+V = [(1,-1,2)-(6,-6,2)]+(1,1,1)\\\\\ [P-2U]+V = [(1-6), (-1-(-6)) , (2-2)]+(1,1,1)\\\\\ [P-2U]+V = [(-5.5.0)]+(1,1,1)\\\\\ [P-2U]+V = (-5,5,0)+(1,1,1)\\\\\ [P-2U]+V = (-5+1),(5+1),(0+1)\\\\\ [P-2U]+V = (-4,6,1)
Perguntas similares