Question

a)(3/2+2/5)+(5\4-2\3)=

b)(3\4+4\3).(8\7-7\4)=

c)(7\8-5\6)+(8\9-7\9)=

d)1\2.3\5-1\3.2\5+3\2.7\3=

e)1+(1\2-1\5)-(7\4-5\4

Answer 1

A.
$( \frac{3}{2} + \frac{2}{5} ) + ( \frac{5}{4} - \frac{2}{3} ) = \\ ( \frac{15 + 4}{10} ) + ( \frac{15 - 8}{12}) = \\ ( \frac{19}{10} ) + ( \frac{7}{12}) = \frac{114 + 35}{60} = \frac{149}{60}$

B.
$( \frac{3}{4} + \frac{4}{3} ) * ( \frac{8}{7} - \frac{7}{4} ) = \\ ( \frac{9 + 16}{12}) * ( \frac{32 - 49}{28} ) = \\ \frac{25}{12} * ( \frac{-17}{28} ) = \frac{-425}{336}$

C.
$( \frac{7}{8} - \frac{5}{6} ) + ( \frac{8}{9} - \frac{7}{9} ) = \\ ( \frac{21 - 20}{24} ) + \frac{1}{9} = \\ \frac{1}{24} + \frac{1}{9} = \frac{3 + 9}{72} = \frac{12}{72}$

D.
$\frac{1}{2} * \frac{3}{5} - \frac{1}{3} * \frac{2}{5} + \frac{3}{2} * \frac{7}{3} = \\ \frac{3}{10} - \frac{2}{15} + \frac{21}{6} = \\ \frac{9 - 4 + 105}{30} = \frac{100}{30}$

E.
$1 + ( \frac{1}{2} - \frac{1}{5} ) - ( \frac{7}{4} - \frac{5}{4}) = \\ 1 + ( \frac{5 - 2}{10} ) - \frac{2}{4} = \\ 1 + \frac{3}{10} - \frac{2}{4} = \\ \frac{20 + 6 - 10}{20} = \frac{16}{20}$