Question

Calcule as derivadas abaixo:

y= x³/2 + 3x/2

e

y= ³$\sqrt{x}$

Answer 1

Bom dia

y = x³/2 + 3x/2

derivada

y' = 3x²/3 + 3/2 

y = ³√x = x^(1/3)

deivada

y' = (1/3)*x^(1/3 - 1)
y' = (1/3)*x^(1/3 - 3/3)
y' = (1/3)*x^(-2/3)

y' = 1/(3*x^(2/3)) 

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