Question

interpole 4 meios aritmeticos entre 14 e 49 ?

Answer 1

(14,a2,a3,a4,a5,49)
a1=14
a6=49

an=a1+(n-1).r
49=14+(6-1).r
49=14+5r
5r=49-14
5r=35
r=7

a2=14+7=21
a3=21+7=28
a4=28+7=35
a5=35+7=42