Question

como resolver: 
x²(x²-6) = 3(x^4-2x²)

Answer 1

Olá Lohanna,

$x^2(x^2-6)=3(x^4-2x^2).\\ x^4-6x^2=3x^4-6x^2\\ x^4-3x^4-6x^2+6x^2=0\\ -2x^4=0\\ (-2x^2)^2=0\\\\ x^2=k\\\\ -2k^2=0\\\\ k^2= \dfrac{~~0}{-2}\\\\ k^2=0\\ k=\pm \sqrt{0}\\\\ k=\pm0\\\\ k'=k''=k'''=k''''=0\\\\ \large\boxed{S=\{0,0,0,0\}}$

Tenha ótimos estudos =))