Question

x²-4\X+2 +x²-3x +2\x-1,para x=4

Answer 1

$\frac{x^2-4x}{x+2} + \frac{x^2-3x+2}{x-1}$ para x = 4

$\frac{x^2-4x}{x+2} + \frac{x^2-3x+2}{x-1}=\frac{4^2-4\cdot4}{4+2} + \frac{4^2-3\cdot4+2}{4-1} =\frac{16-16}{4+2} + \frac{16-12+2}{4-1} \\ \\=\frac{0}{6} + \frac{6}{3} =0+ 2 = 2$