Question

Determine x, y e z, sabendo que x + y = 6 e que a // b // c // d.

Answer 1

$\frac{x}{1,3}= \frac{y}{2,6}= \frac{z}{3,25} =k$

Com essas relaçoes podemos concluir que:
$\frac{x}{1,3}=k\Rightarrow x=1,3k\\ \\ \frac{y}{2,6}=k\Rightarrow y=2,6k\\ \\ \frac{z}{3,25}=k\Rightarrow z=3,25k\\ \\---------------\\ x+y=6\\ \\1,3k+2,6k=6\\ \\3,9k=6\\ \\ \frac{39k}{10}=6\\ \\ k=\frac{10\cdot6}{39}\\ \\ k=\frac{60^{:3}}{39_{:3}}\\ \\ k=\frac{20}{13}$

$\\ \frac{x}{1,3}=k\Rightarrow x=1,3k\Rightarrow x=1,3\cdot \frac{20}{13}\Rightarrow x= \frac{26}{13}\Rightarrow x= 2 \\ \\ \frac{y}{2,6}=k\Rightarrow y=2,6k\Rightarrow y=2,6\cdot \frac{20}{13}\Rightarrow y= \frac{52}{13}\Rightarrow x= 4\\ \\ \frac{z}{3,25}=k\Rightarrow z=3,25k\Rightarrow z=3,25\cdot \frac{20}{13}\Rightarrow z= \frac{65}{13}\Rightarrow z= 5$