Question

Me ajude, por favor! 

${ \frac{ a^2b^3a^-^3}{b^-^1} } -(-b) para a = -1 e b = -2$

Answer 1

$\frac{ a^{2}. b^{3} . a^{-3} }{ b^{-1} } -(-b)$

$\frac{ (-1)^{2}. (-2)^{3} . (-1)^{-3} }{ (-2)^{-1} }-(-(-2))$

$\frac{ 1.( -8).( \frac{1}{(-1)})^{3} }{ \frac{1}{(-2)}^{1} } -(2)$

$\frac{1.(-8).(-1)}{ (-\frac{1}{2}) } -2$

$\frac{8}{ \frac{1}{2} } -2$

$\frac{8}{1} . \frac{2}{1} -2$

$\frac{16}{1} -2$

$16-2=\boxed{\boxed{14}}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ ok$