Question

insira 4 meios geométricos  entre 1 e 243

Answer 1

q=?                         an=a1.q^n-1
n=6                        243=1.q^6-1        
na=243                  243=1.q^5
                               3^5=1.q^5
                                    q=3/1
                                    q= 3
PG (1,3,9,27,81,243).

Answer 2

Boa tarde!

Dados:

a1 → 1

an → 243

n → 2+4 = 6 ( Dois existentes mais quatro que serão adicionados)

q → ?

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An=a1·q⁽ⁿ⁻¹⁾

243=1·q⁽⁶⁻¹⁾

243=1·q⁵

243/1=q⁵

243=q⁵

q= ⁵√243

q=3

___________

P.G→ (1, 3, 9, 27, 81, 243)

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Att;Guilherme Lima