Question

i)3(2x-1)=-2(x+3) j)5x-3(x+2)=15 k)2x+3x+9=8(6-x) l)4(x+10)-2(x-5)=0 m)3(2x+3)-4(x-1)=3 n)7(x-1)-2(x-5)=x-5 o)2(3-x)=3(x-4)+15 p)3(5-x)-3(1-2x)=42 q)(4x+6)-2x=(x-6)+10+14 r)(x-3)-(x+2)+2(x-1)-5=0
S)3x-2(4x-3)=2-3(x-1)T)3(x-1)-(x-3)+5(x-2=18 u)5(x-3)-4(x+2)=2+3(1-2x)

Answer 1

I)3(2x-1)=-2(x+3) ∴  6x - 3 = -2x - 6 ∴ 6x +2x = -6 + 3 ∴ 8x = -3 ∴ x= -3/8
j)5x-3(x+2)=15 ∴ 5x - 3x - 6 = 15 ∴ 2x = 21 ∴ x=21/2
k)2x+3x+9=8(6-x) ∴ 5x = -9 + 48 - 8x ∴ 13x = 39 ∴ x = 39/13 = 3
l)4(x+10)-2(x-5)=0 ∴ 4x + 40 - 2x + 10 = 0 ∴ 2x = -50 ∴ x= -50/2 = -25
m)3(2x+3)-4(x-1)=3 ∴ 6x + 9 -4x +4 = 3 ∴ 2x = 10 ∴ x = 5
n)7(x-1)-2(x-5)=x-5 ∴ 7x -7 - 2x +10 = x -5 ∴ 4x = -8 ∴ x= -2
o)2(3-x)=3(x-4)+15 ∴ 6 -2x = 3x -12 + 15 ∴ -5x = -3 ∴ x= 3/5
p)3(5-x)-3(1-2x)=42 ∴ 15 - 3x - 3 + 6x = 42 ∴ 6x = 42 -12 ∴ x= 30/6 = 5
q)(4x+6)-2x=(x-6)+10+14 ∴ 4x +6 -2x -x = -6 + 24 ∴ x = 12
r)(x-3)-(x+2)+2(x-1)-5=0 ∴ x - 3 - x - 2 + 2x - 2 - 5 = 0 ∴ 2x = 12 ∴ x = 6
S)3x-2(4x-3)=2-3(x-1) ∴ 3x - 8x + 6 = 2 -3x + 3 ∴ -2x = -1 ∴ x = 1/2
T)3(x-1)-(x-3)+5(x-2=18 ∴ 3x - 3 - x + 3 + 5x - 10 = 18 ∴ 7x = 18 + 10 ∴ x = 28/7 = 4
u)5(x-3)-4(x+2)=2+3(1-2x) ∴ 5x -15 -4x -8 = 2 + 3 - 6x ∴ 7x = 28 ∴ x = 28/7 = 4