• Matéria: Matemática
  • Autor: carolrb10
  • Perguntado 8 anos atrás

Reduza a uma unica potencia :
A) (7^{4}/7^{3})^{2} =
B) (11^{4})^{5} : (11^{2})^{2} =
C) 2^{3}^{2} X (2^{3})^{2} =
D)256 X 4^{2} / 8^{3} =
E)27 X 81/243 =
F) 3^{6} X 27^{2} / 243 =
G) (x^{2} X x^{3})^{3} =
H) (a^{3} : a^{2} )^{4} =
I) (m^{5})^{2} =
pff me ajudem

Respostas

respondido por: andreluizdeoliveira
46
A) ( \frac{7^4}{7^3} )^2=(7^4^-^3)^2=(7^1)^2=7^1^.^2=7^2

B) 
(11^4)^5:(11^2)^2=11^4^.^5:11^2^.^2=11^2^0:11^4=11^2^0^-^4=11^1^6

C) 
2^3^2.(2^3)^2=2^3^2.2^3^.^2=2^3^2.2^6=2^3^2^+^6=2^3^8

D) 
256. \frac{4^2}{8^3}=2^8. \frac{(2^2)^2}{(2^3)^3}=2^8. \frac{2^4}{2^9}=2^8.2^4^-^9=2^8.2^-^5=2^8^+^(^-^5^)=2^3

E) 
27. \frac{81}{243}=3^3. \frac{3^4}{3^5}=3^3.3^4^-^5=3^3.3^-^1=3^3^+^(^-^1^)=3^2

F) 
3^6. \frac{27^2}{243}=3^6. \frac{(3^3)^2}{3^5}=3^6. \frac{3^6}{3^5}=3^6.3^6^-^5=3^6.3^1=3^6^+^1=3^7

G) 
 (x^{2}. x^{3})^3=(x^2^+^3)^3=(x^5)^3=x^5^.^3=x^1^5

H) 
(a^3:a^2)^4=(a^3^-^2)^4=(a^1)^4=a^4

I) 
(m^5)^2=m^5^.^2=m^1^0
respondido por: isabelinha3108
1

Resposta:

observação: ^3 = ³  

A) (7^4/7³) ² = (7^4-³) ² = (7¹) ² = 7¹.² =7²

B) (11^4) ^5: (11²) ² = 11^4.^5 = 11^20 : 11^4 = 11^20 - ^4 = 11^16

C) 2³ ². (2³) ² = 2³ ². 2³.² = 2³ ². 2^6 = 2³ ² + ^6 = 2³ ^8

D) 256.4²/8³ = 2^8. (2²) ²/(2³) ³ = 2^8. 2^4/2^9 = 2^8. 2^4-^9 = 2^8 .2-^5 = 2^8+ (-^5) = 2³

E) 27. 81/243 = 3³. 3^4/3^5 = 3³. 3^4-3^5 =3³.3-¹ = 3³+(-¹) =3²

F) 3^6 .27²/243 = 3^6.(3³)²/3^5 = 3^6 . 3^6/3^5 = 3^6 . 3^6-^5 = 3^6 .+¹= 3³+(-¹) = 3^7

G) (x².x³) ³ = (x²+³) ³= (x^5) ³= x^5- ³= x^5- ³= x ¹^5

H) ( a³: a²)^4 = (a²-³)^4 = (a¹)^4 = a^4

I) (m^5) ² = m^5. ² = m^10

Explicação passo-a-passo:

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