Question

Radicais : 5 (raiz quadrada de 3) - 4 (raiz quadrada de 12) + (raiz quadrada de 192)

Answer 1

$5 \sqrt{3}-4 \sqrt{12}+ \sqrt{192}=$

$5 \sqrt{3}-4 \sqrt{2^2.3}+ \sqrt{2^2.2^2.2^2.3}=$

$5 \sqrt{3}-4+2 \sqrt{3}+ 2.2.2\sqrt{3}=$

$5 \sqrt{3}-2 \sqrt{3}+ 8\sqrt{3}=$

$(5-2+8) \sqrt{3}=$

$(3+8) \sqrt{3}=$

$11\sqrt{3}$