Question

simplifique:

a)3*√200
b)12*√81
c)6*√1000
d)20*√1024

Answer 1

Olá, tudo bem?

$a)\,\,3.\sqrt{200}=3.\sqrt{2^{2}.2.5^{2}}=3.2.5.\sqrt{2}=\boxed{30\sqrt{2}}\\\\ b)\,\,12.\sqrt{81}=12.\sqrt{9^{2}}=12.9=\boxed{108}\\\\ c)\,\,6.\sqrt{1000}=6.\sqrt{10^{2}.10}=6.10\sqrt{10}=\boxed{60\sqrt{10}}\\\\ d)\,\,20.\sqrt{1024}=20.\sqrt{2^{10}}=20.2^{\frac{10}{2}}=20.2^{5}=20.32=\boxed{640}$

Muito Obrigado pela confiança nesse trabalho!! :-)