Question

determine a PA cujo primeiro termo vale 1 e o décimo termo vale 16

Answer 1

an=a1+(n-1)*r
16=1+(10-1)*r
15=9*r
r=15/9=5/3
r=1,66666...

PA(1, 2.66 , 4.32, 5.98, 7.64, 9.3, 10.96, 12.62, 14.28, 16)

está aí a PA

espero ter ajudado

Answer 2

Termo geral da PA

$a_{n} = a_{1} + (n-1)r \\ \\ a_{10}= a_{1} +(10-1)r \\ \\ a_{10}= a_{1}+9r \\ \\ 16=1+9r \\ \\ 16-1=9r \\ \\ 9r=15 \\ \\ r= \frac{15}{9} \\ \\ r= \frac{5}{3} \\ \\ a_{2} = a_{1} +r \\ \\ a_{2}=1+ \frac{5}{3} = \frac{3+5}{3} = \frac{8}{3} \\ \\ a_{3}= a_{2}+r \\ \\ a_{3} = \frac{8}{3} + \frac{5}{3}= \frac{13}{3} \\ \\ PA(1, \frac{8}{3}, \frac{13}{3}, ...)$