aplicando as propriedades das potencias, escreva a expressão abaixo como uma unica potencia de base 2
4 ^4.32^ 4. 2^-9 / 8^-1. 64^2 =
Respostas
respondido por:
1
vamos lá...
![(4^4.32^4.2^{-9})\div(8^{-1}.64^2)=[(2^2)^4.(2^5)^4.2^{-9}]\div[(2^3)^{-1}.(2^6)^2]= \\ \\ (2^8.2^{20}.2^{-9})\div(2^{-3}.2^{12})= \\ \\ ( 2^{8+20-9} )\div( 2^{-3+12} )= \\ \\ 2^{19} \div2^9= \\ \\ 2^{19-9}=2^{10}](https://tex.z-dn.net/?f=%284%5E4.32%5E4.2%5E%7B-9%7D%29%5Cdiv%288%5E%7B-1%7D.64%5E2%29%3D%5B%282%5E2%29%5E4.%282%5E5%29%5E4.2%5E%7B-9%7D%5D%5Cdiv%5B%282%5E3%29%5E%7B-1%7D.%282%5E6%29%5E2%5D%3D+%5C%5C++%5C%5C+%282%5E8.2%5E%7B20%7D.2%5E%7B-9%7D%29%5Cdiv%282%5E%7B-3%7D.2%5E%7B12%7D%29%3D+%5C%5C++%5C%5C+%28+2%5E%7B8%2B20-9%7D+%29%5Cdiv%28+2%5E%7B-3%2B12%7D+%29%3D+%5C%5C++%5C%5C++2%5E%7B19%7D+%5Cdiv2%5E9%3D+%5C%5C++%5C%5C+2%5E%7B19-9%7D%3D2%5E%7B10%7D "(4^4.32^4.2^{-9})\div(8^{-1}.64^2)=[(2^2)^4.(2^5)^4.2^{-9}]\div[(2^3)^{-1}.(2^6)^2]= \\ \\ (2^8.2^{20}.2^{-9})\div(2^{-3}.2^{12})= \\ \\ ( 2^{8+20-9} )\div( 2^{-3+12} )= \\ \\ 2^{19} \div2^9= \\ \\ 2^{19-9}=2^{10}")
Perguntas similares
7 anos atrás
9 anos atrás
9 anos atrás
9 anos atrás