Question

sendo ㏒2= 0,3, ㏒3=0,5 e ㏒5=0,7 calcule

a)㏒ 1/125

Answer 1

log1=
10^x=1
10^x=10^0
x=0
log1=0

log1/125=
log1-log125=
0-log5^3=
0-3log5=
0-3.0,7=
0-2,1=
-2,1