Question

como fazer essa questão do 2 grau x(x-1)-6x=2-2x(x-3) preciso urgente

Answer 1

$x(x-1)-6x=2-2x(x-3) \\ \\ x^{2} -x -6x = 2 - 2x^2 + 6x \\ \\ x^{2} -7x = -2 x^{2} +6x + 2 \\ \\ x^{2} -7x + 2x^2 - 6x - 2 = 0 \\ \\ 3 x^{2} -13x - 2 = 0$

Resolvendo por Bhaskara:

$x = \frac{-b \pm \sqrt{b^2 -4*a*c}}{2*a}$

$3x^2 - 13x - 2 = 0$

a=3, b=−13, c=−2
Δ=b2−4ac
Δ=(−13)2−4*(3)*(−2)
Δ=169+24
Δ=193
$x = \frac{-b \pm \sqrt{\triangle}}{2*a} \\ \\ x = \frac{-(-13) \pm \sqrt{193}}{2*3} \\ \\ x = \frac{13 \pm \sqrt{193}}{6} \\ \\ x' = \frac{13 + \sqrt{193}}{6} \\ \\ \\ x'' = \frac{13 - \sqrt{193}}{6}$


S = {$\frac{13 + \sqrt{193}}{6}, \frac{13 - \sqrt{193}}{6}$}