Question

1) resolvendo equações:
a)[tex] \frac{x-3}{2} + \frac{2x+1}{3} = \frac{x-1}{2}

Answer 1

Olá.

$\dfrac{x-3}{2}+\dfrac{2x+1}{3}=\dfrac{x-1}{2}\\\\\dfrac{3\cdot(x-3)+2\cdot(2x+1)}{6}=\dfrac{x-1}{2}\\\\\dfrac{3x-9+4x+2}{6}=\dfrac{x-1}{2}\\\\\dfrac{7x-7}{6}=\dfrac{x-1}{2}\\\\6\cdot(x-1)=2\cdot(7x-7)\\6x-6=14x-14\\6x-14x=-14+6\\-8x=-8\cdot(-1)\\8x=8\\\\x=\dfrac{8}{8}\\\\\boxed{x=1}$

A imagem é pra caso o LaTex falhe.
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Bons estudos.